Answer :


Given


Surface area of the plate, A = 10 cm2 = 10 × 10−4 m2



Thickness of copper deposited, t = 10 μm = 10−5 m



Density of copper = 9000 kg/m3


Electrochemical equivalent of copper –3 × 10–7 kg C–1


specific heat capacity of water – 4200 J kg–1 K–1


Volume, V of copper deposited,


V = (2t)


Where


A is the area of the plates


t is the thickness of the plates


Putting the values in the above formula, we get









We know, mass of copper deposited,


m = Volume × Density





Using the Faraday's Laws


m = ZQ


where


m = mass of the substance


Q= charge


Z= Electrochemical equivalent


Putting the values in the above formula, we get
18 × 10−5 = 3 × 10−7 × Q


Q = 6 × 102 C



Now,


The energy spent by the cell will be = Work done by the cell



W = V× Q


Where


V is the potential difference


Q is the charge


Putting the values in the above formula, we get



= 12 × 6 × 102



= 72 × 102 = 7.2 kJ



Let us take ∆θ as the rise in temperature of water.


If this amount of energy is used to heat 100 g of water, then-


Q = c×m ×∆θ


Where,


c= specific heat of water


Q= Heat


m = mass of water


∆θ = change in temperature


Substituting



7.2 × 103 = 100 × 10−3 × 4200 × ∆θ



θ = 17 K


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