Answer :

Given,


Area of the two wings, A = 2 × 25 = 50 m2


Air Velocity over wings, v1 = 234 km/h = 65 m/s


Air Velocity below wings, v2 = 180 km/h = 50 m/s


Density of the air, ρ = 1 kg/m3


Bernoulli’s equation,


( neglecting potential energy)


Let, P1 = pressure over wings


P2 = pressure below wings





= 862.5 pa


We have,



Where,


ΔP = change in pressure = P2 – P1


A = area


F = 862.5 pa × 50 m2


= 43125 N


As per Newton’s second law,


F = mg


Where,


F = force


g = acceleration due to gravity


mass of the plane,



Thus,


Mass of the plane, m ≈ 4400 kg


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