Q. 48

A piston is fitted in a cylindrical tube of small cross section with the other end of the tube open. The tube resonates with a tuning fork of frequency 512 Hz. The piston is gradually pulled out of the tube and it is found that a second resonance occurs when the piston is pulled out through a distance of 32.0 cm. Calculate the speed of sound in the air of the tube.

Answer :

Given:
Frequency of tuning fork



Let the speed of sound in the tube be
.



Let
be the length at which the piston resonates for the first time and be the length at which the piston resonates for the second time.


We have:


Velocity



Hence, the speed of the sound in the tube is 328 m/s.


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