Q. 475.0( 1 Vote )

A particle moves in a circle of diameter 1.0 cm under the action of a magnetic field of 0.40 T. An electric field of 200 V m–1 makes the path straight. Find the charge/mass ratio of the particle.

Answer :

Given-
Diameter of the circle = 1.0 cm



Thus, radius of circle, r = = 0.5 × 10−2 m



Magnetic field, B = 0.40 T



Electric field, E = 200 V m−1


From the question we can confer that, the particle is moving in a circle under the action of a magnetic field.


But when an electric field is applied on the particle, it moves in a straight line.



So, we can say that the electric field is balanced by the magnetic field ie,



Magnetic force, we know, Lorentz force F is given by -



where,


q = charge on an electron


v = velocity of the electron


B=magnetic field


θ= angle between B and v






The radius of the circular path described by a particle in a magnetic field r,



where,


m is the mass of a proton


v= velocity of the particle


B = magnetic force


q= charge on the particle = C





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