Q. 15

# A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 × 10^{–4}. Calculate the particle’s mass and identify the particle.

Answer :

Broglie expression is given by

m is the mass

h is he planks constant

v is velocity

is wavelength

(4)/(1) =>

of proton is

of neutron is

From the above the particle must be neutron.

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