Q. 15

A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 × 10–4. Calculate the particle’s mass and identify the particle.

Answer :

Broglie expression is given by



m is the mass


h is he planks constant


v is velocity


is wavelength






(4)/(1) =>




of proton is


of neutron is


From the above the particle must be neutron.


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