Answer :

x(t) = x_{0}( 1 – e^{-yt})

(a) The particle starts at t = 0 that is at x = 0.

For velocity, we need to differentiate the given equation with respect to time.

At t = 0, v = . This is the starting velocity of the object.

(b) x(t) will be maximum when ‘t’ approaches infinity and will be equal to x_{0}. It is increasing from zero to x_{0} with time.

v(t) will be maximum at t=0 and will be x_{0}y. It will be minimum as ‘t’ approaches infinity. Clearly it is decreasing with time.

a(t) will be maximum as ‘t’ approaches infinity and will be equal to 0. Its minimum value will be (–x_{0}y^{2}) at t = 0. We can note that acceleration is increasing (from (–x_{0}y^{2}) to 0) with increasing time.

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