# A particle covers

Let the initial speed be u m/s and speed after 5s be v1m/s.

Let acceleration of the particle be a m/s2.

v1 = u + 5a …(using v = u + at) …(1)

Now for first 5s, distance s1

(2)

For next 3s, v1 will be its initial velocity

and distance s2

...(3)

Now s1-s2 = 0

Putting value of u in equation (2), we get

…(5)

So (from equation (4))

Given, Distance in 8sec = 10m + 10m = 20m

Distance in 10sec

Distance covered in next 2sec

=

= 8.33 m

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