Q. 104.2( 13 Votes )

A parallel plate

Answer :

Initially, the energy stored in the capacitor is,

And the charge on the capacitor is q = CV,

When the capacitor is connected to another capacitor of same capacitance the charge gets redistributed equally amongst the two capacitors, q’ = CV/2,

The new energy stored in each capacitor is,

Total Energy stored in the combined system,

Ratio of the energy stored in the combined system to that stored initially in the single capacitor is,

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A parallel plate Physics - Board Papers