Answer :

Given,


Area, A = 400cm2 = 400 × 10–4m2


distance between plates d = 1cm = 1× 10–3m


voltage V = 100V


Thickness t = 0.5 = 5 × 10–4m


dielectric constant, k = 5


The capacitance of the capacitor without the dielectric slab is given by


Where,


A= Plate Area


d= separation between the plates,


0 = Permittivity of free space = 8.854 × 10-12 m-3 kg-1 s4 A2




When the dielectric slab is inserted, the capacitance becomes



where, t is the thickness of the slab





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