A parallel-plate

Given:

Area of the plate, A is 100 cm²

Separation of the plate, d is 1 cm

Dielectric constant of the glass plate is 6

Thickness of the glass plate is 6.0 mm

Dielectric constant of an ebonite plate is 4.0

The given system of the capacitor will connected as shown in the fig.

The capacitors behave as two capacitors connected in series.

Let the capacitances be C₁ and C₂.

Now,

capacitance c

Where, A = area

k = dielectric constant of the material placed

d=separation between the plates

and is permittivity of free space whose value is

Now, first capacitor C₁

1)

and

2)

Hence, the net capacitance for a series connected capacitor is given by-

3)

from 1),2), and 3)