Answer :

(a) The mirror isobar of is


(b) has a greater binding energy than that of


Explanation


(a).


Mirror isobars are isobars whose mass number is same and the number of protons of is equal to the number of the neutrons of and the number of neutron of is equal to the proton of the . Therefore, the mass number of both the elements is



So according to mirror isomers



Then the mass number can also be formed as



Now to find the mirror isobar of nuclide, we know that mass number of sodium (Na) = 23, and another similar case is that of Magnesium (Mg) = 23, with sodium has 11 proton and 12 neutron and magnesium with 12 proton and 11 neutron.


(b).


To find the binding energy of the elements of Sodium and Magnesium; we use the formula for calculation of Binding energy from mass defect.


To find the value of atomic mass of an element we use:



where


is the number of proton, is the number of neutrons, the mass of a single proton = , the mass of a single neutron is


So firstly for Sodium,


We need the actual mass of Sodium which is


The atomic mass of Sodium is from the calculation of proton and neutrons is



To convert the mass defect into we multiply it by


Therefore, the Binding Energy of the element Sodium is



Similarly for Magnesium, we get the Binding Energy as


We need the actual mass of Magnesium which is


The atomic mass of Magnesium is from the calculation of proton and neutrons is



To convert the mass defect into we multiply it by Therefore, the Binding Energy of the element Magnesium is



Hence, as we can see that the Binding energy of magnesium is greater than that of Sodium, the is another reason apart from the value is because of the number of proton present in the nucleus, even number of protons tends to have more Binding Energy than that of odd number of protons.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Calculate the eneHC Verma - Concepts of Physics Part 2

A nuclide 1 is saPhysics - Exemplar

The mass of a H-aPhysics - Exemplar

Are the nucleons Physics - Exemplar

In pair annihilatPhysics - Exemplar

The binding energPhysics - Exemplar

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Calculate the maxHC Verma - Concepts of Physics Part 2