Answer :

As the galvanometer limit is 1mA we need to find the voltage drop across it’s to measure the voltage. For that we will replace the galvanometer with a resistance equal to its internal resistance.

The maximum voltage drop across the 10Ω resistance will be,

V = 10 × 10-3 v

=10-2 v

So, D point should not exceed 10-2v.

Using kcl in the branch AD

= 2 kΩ

Now, from BD we get

=18 kΩ

From CD we get

=180 kΩ

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