Answer :

As the galvanometer limit is 1mA we need to find the voltage drop across it’s to measure the voltage. For that we will replace the galvanometer with a resistance equal to its internal resistance.



The maximum voltage drop across the 10Ω resistance will be,


V = 10 × 10-3 v


=10-2 v


So, D point should not exceed 10-2v.


Using kcl in the branch AD




= 2 kΩ


Now, from BD we get


=18 kΩ


From CD we get


=180 kΩ


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