Q. 175.0( 1 Vote )

A moving-coil galvanometer has a 50-turn coil of size 2 cm × 2 cm. It is suspended between the magnetic poles producing a magnetic field of 0.5 T. Find the torque on the coil due to the magnetic field when a current of 20 mA passes through it.

Answer :


number of turns in the coil n=50

area of the cross section of the coil, A = 4 cm2

magnetic field strength due to the presence of the pole B =0.5 T

current flow through the coil I =20mA = 20X10-3


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