Let the weight of dihydrogen be 20 g and the weight of dioxygen be 80 g.
Then, the number of moles of dihydrogen:
n(H2) = 20/2 = 10 moles
The number of moles of dioxygen:
n(O2) = 80/32 = 2.5 moles
Total pressure of the mixture, p(total) = 1 bar
Then, partial pressure of dihydrogen:
= 0.8 bar
Hence, the partial pressure of dihydrogen is 0.8 bar.
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