Q. 165.0( 1 Vote )

Given:

Temperature at which meter scale gives accurate reading: T1=20° C

Change in Length required: Δ L=0.055mm = 0.055 x 10-3 m.

Original Length: L= 1 m.

Coefficient of linear expansion of steel: α = 11 x 10-6 ° C-1.

Formula used:

Now, we have the direct formula for change in length due to thermal expansion:

Where Δ L is the change in length.

Where Δ T is the change in temperature,

it can be T1+T2 OR T1-T2.

First let’s take T1-T2.

Now, let’s take T1+T2,

Hence, the range of the temperature within which this experiment can be performed with the given metre scale is 15° C to 25° C.

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