Q. 245.0( 3 Votes )

A metal complex h

Answer :

(i) The isomer A = [Cr(NH3)4BrCl]Cl

The isomer B = [Cr(NH3)4Cl2]Br

(ii) Hybridization of Cr in both is d2sp3

(iii) 3. 87 BM


(i) Since, [Cr(NH3)4BrCl]Cl + AgNO3AgCl

WE know that AgCl is a white precipitate which is readily soluble in dilute aqueous ammonia we can tell that it is isomer A


Since, [Cr(NH3)4Cl2]Br + AgNO3AgBr

We know that AgBr gives a pale yellow precipitate which is soluble in concentrated ammonia we can tell that isomer B is the right answer.

(ii) Cr3+ is in 3d3 system; we can tell that its hybridization is d2sp3.

[NOTE:read about the different systems to know what falls in which system and its hybridization to learn this concept easily]

(iii) To find the magnetic moment:

Formula :

Where, n = the number of unpaired electrons

In Cr3 + we have d3 outermost shell configuration =

1s2 2s2 2[6 3s2 3p6 3d5 4s1 [Ar]3d5 4s1 [Ar]3d3.

Moreover, therefore it has three unpaired electrons

Substitute 3 in the formula

= 3. 87 BM

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