Q. 245.0( 3 Votes )

A metal complex h

Answer :

(i) The isomer A = [Cr(NH3)4BrCl]Cl


The isomer B = [Cr(NH3)4Cl2]Br


(ii) Hybridization of Cr in both is d2sp3


(iii) 3. 87 BM


Explanation:


(i) Since, [Cr(NH3)4BrCl]Cl + AgNO3AgCl


WE know that AgCl is a white precipitate which is readily soluble in dilute aqueous ammonia we can tell that it is isomer A


And


Since, [Cr(NH3)4Cl2]Br + AgNO3AgBr


We know that AgBr gives a pale yellow precipitate which is soluble in concentrated ammonia we can tell that isomer B is the right answer.


(ii) Cr3+ is in 3d3 system; we can tell that its hybridization is d2sp3.


[NOTE:read about the different systems to know what falls in which system and its hybridization to learn this concept easily]


(iii) To find the magnetic moment:


Formula :


Where, n = the number of unpaired electrons


In Cr3 + we have d3 outermost shell configuration =


1s2 2s2 2[6 3s2 3p6 3d5 4s1 [Ar]3d5 4s1 [Ar]3d3.


Moreover, therefore it has three unpaired electrons


Substitute 3 in the formula




= 3. 87 BM


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