Answer :

Given:



The frequency, v of a wave with wavelength λ is given by,


v = c/λ …(1)


(c = speed of light = 3 × 108ms-1)


By using equation (1) we can find frequency for each case,



The equation for photo-electric effect is given as,


Φ0 = hv- eV0


We can rewrite this equation as,


V0 = …(2)


Where,


h = Planck’s constant


c = speed of light = 3 × 108m


λ = wavelength of light


e = charge on each electron = 1.6 × 10-19C



We find that the slope of the graph remains same,


Slope of the line =


From equation (2),


We can write,


Slope = h/e


h = e × slope


h =


h = 6.58 × 10-34 Js


From the same graph, we can infer that, threshold frequency of the metal is 5 × 1014 Hz


i.e. v0 = 5 × 1014Hz


Work function, Φ0 = hv0 …(2)


Where,


h = Plank’s constant = 6.57 × 10-34Js


v0 = threshold frequency


By plugging the data in equation (2), we get,


Φ0 = 6.57 × 10-34Js × 5 × 1014Hz


Φ0 = 3.28 × 10-19 J



Φ0 = 2eV


Hence, the work function of the metal is 2eV.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If light ofPhysics - Board Papers

A. How does one ePhysics - Board Papers