(a) Local atmospheric pressure, Patm = 76 cm of Hg

Gauge pressure = mercury height in (Right limb – Left limb)

Absolute pressure = Atmospheric pressure + Gauge pressure

For figure a:

Gauge pressure = 20 cm of Hg

Absolute pressure = 76 + 20 = 96 cm of Hg

For figure b:

Gauge pressure = -18 cm of Hg

Absolute pressure = 76 - 18 = 56 cm of Hg

(b) Relative density of the mercury = 13.6

13.6 cm of water exerts same pressure as 1cm of mercury exerts.

Thus,

Pressure in the right limb, Pr = Atmospheric + 1 cm of Hg

= 76 + 1 = 77 cm of Hg

Pressure in the left limb, Pl = 58 + h cm of Hg

Height difference between limbs, h = 77 - 58 = 19 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

The weight of an HC Verma - Concepts of Physics Part 1

A solid float in HC Verma - Concepts of Physics Part 1

(a) PressurPhysics - Exemplar

An ideal fluid flPhysics - Exemplar

Streamline flow iPhysics - Exemplar

If water be used HC Verma - Concepts of Physics Part 1

Find the force exHC Verma - Concepts of Physics Part 1

Suppose the glassHC Verma - Concepts of Physics Part 1

Water level is maHC Verma - Concepts of Physics Part 1

At Deoprayag (GarHC Verma - Concepts of Physics Part 1