Answer :


29


Here the distance of the man from the temple is given,


BC = DE = 15 m.


And height of man =BD = CE =1 = 1.75 m


From the ∆ABC,





So,


Now, height of the temple = AC + CE = 8.66 + 1.75 = 10.41


Therefore, height of the temple is 10.41 m.


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