Q. 294.2( 5 Votes )
A man who is <spa
Here the distance of the man from the temple is given,
BC = DE = 15 m.
And height of man =BD = CE =1 = 1.75 m
From the ∆ABC,
Now, height of the temple = AC + CE = 8.66 + 1.75 = 10.41
Therefore, height of the temple is 10.41 m.
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