Q. 283.9( 7 Votes )
A man of height 1 .5 m sees the top of a tree and the angle of elevation of the top at his eye is 60°. Find the height of the tree if the distance of the man from the tree is 36 m.
Here distance of the man from tree is given
BC = DE = 36 m
And height of man = BD = CE =1.5 m
From the ∆ABC,
Now, height of the tree = AC + CE
= 62.35 + 1.5
Therefore, height of the tree is 63.85 m.
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