Answer :

Here, we have a particular value of No. of turns per unit Length and Current in the coil in order to obtain the given magnetic field.


The Required Magnetic field B = 100 G = 100 × 10–4= 10–2 T


Maximum Number of turns per unit length, n = 1000/m


Maximum Current flowing in the coil, I = 15 A


Permeability of free space, μ0 = 4π × 10–4TmA-1


We know magnetic field for a solenoid is given by


B = 𝜇 0nI


Where,


B is the magnetic field


n is the Number of turns of the coil per unit length


I is the current in the coil


𝜇 �0 is the permittivity of free space


Explanation: here we can change the number of turns per unit length n (maximum 1000 turns per m) and current I (maximum 15A) since 𝜇o is a constant and we have to obtain a fixed value of magnetic field B = 10-2T, so we will alter values of n and I accordingly


Using the formula B = 𝜇 0nI


We get, B/𝜇 0 = nI


So,


= 7957.74 A/m ≈ 8000 A/m


If we take number of turns of coil N = 400,


If we take length of the coil L = 50 cm = 0.5m,


No. of turns per unit length, n = N/L= 400/0.5 = 800/m


(less than 1000/m)


If we take current I = 10 A


(less than 15 A),


We get nI = 8000 A/m


Area of Coil A = 10-3 m2 = πr2, where r is radius of coil


We get



r = 0.017m


The values of N, L and I are within the proposed limits, Though there can be other values as well.


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