Answer :

A line l with A(1, 0) and B(2, 3) as end points is given

l ⊥ AB and AC : CB = 1 : n

Now coordinates of C are

or which is C.

Now slope of AB = = 3

Now slope of l = -

(as m_{1}m_{2} = -1)

equation of l is:

y – y_{1} = n(x – x_{1})

or y- =

3 = -

3(n + 1)y – 9n = -(n + 1)x + (n+2)

(1 + n)x + 3(1 + n)y = 10n + 2

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