Q. 84.4( 7 Votes )

# A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm^{2}. What maximum pressure would the smaller piston have to bear?

Answer :

Maximum mass of a car that can be lifted (m) = 3000 kg

Area of cross section of piston carrying the load (A_{1}) = 452 cm^{2}

= 0.0452 m^{2}

Maximum force exerted by the car due to its weight (F) = mg

= 3000kg × 9.8m/s^{2}

= 29400 kgm/s^{2}

Pressure on the piston lifting the car P = F/A

=

= 6.504 × 10^{5} Pa

__Pressure is transmitted equally in all the directions of a fluid. Therefore the maximum pressure on the smaller piston is 6.504 × 10 ^{5} Pa.__

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