Q. 84.4( 7 Votes )

# A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2. What maximum pressure would the smaller piston have to bear?

Maximum mass of a car that can be lifted (m) = 3000 kg

Area of cross section of piston carrying the load (A1) = 452 cm2

= 0.0452 m2

Maximum force exerted by the car due to its weight (F) = mg

= 3000kg × 9.8m/s2

= 29400 kgm/s2

Pressure on the piston lifting the car P = F/A

=

= 6.504 × 105 Pa

Pressure is transmitted equally in all the directions of a fluid. Therefore the maximum pressure on the smaller piston is 6.504 × 105 Pa.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Fluid Statics67 mins
Wave mechanical model of atom66 mins
Elasticity52 mins
NCERT Exemplar | Body Fluids and Circulation Part 232 mins
Quiz on wave mechanical model of atom40 mins
Do You know everything about your heart?43 mins
Top 10 Questions of Body fluids & Circulation (Quiz)32 mins
Check your understanding of Body fluids & Circulation40 mins
Heart44 mins
Body Fluids & Circulation | NEET Exemplar Important Questions45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses