Q. 20

(a) How will you

Class 12th Chemistry - Board Papers

Answer :

(a) (i)

2000px-PhenolOxidation.svg.png

(ii) OMgX OH

CH₃COCH₃ +CH₃MgX → CH₃-C-CH₃→ CH₃-C-CH₃

(propanone)CH₃ CH₃

(2-methyl propan-2-ol)

(b) Propanol have higher boiling point than that of butane due to presence of hydrogen bonding between propane molecules whereas no such bonding is present in butane. Due to this propanol boil at higher temperature than butane.

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