Q. 193.8( 16 Votes )
A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
Answer :
What we want to find is work done. We know that the work done to stop a moving body is the total kinetic energy of the body.
∴ Work Done = KE = KErot + KEtran
Where KErot is rotational kinetic energy and
KEtran is translational kinetic energy
KErot = 1/2 Iω2
KEtran = 1/2 Mv2
Where M is mass of hoop
I is moment of inertia of hoop
v is velocity of centre of mass
ω is angular velocity
Now the given values are,
Mass of hoop, M = 100 Kg
Radius of hoop, R = 2 m
Speed of centre of mass of hoop, v = 20 Cm s-1
= .2 m s-1
The axis of rotation of hoop passes through point B, we know that velocity of point O (centre of loop) is v. If ω is angular velocity of hoop then,
v = R ω (R is Distance between axis and centre(O))
Where ω is angular velocity.
i.e. ω = v/R = 0.2/2 = .1 s-1
Moment of inertia of hoop, I = MR2
Where, M is mass of hoop
R is Radius of hoop
∴ I = 100(2)2
I = 400 Kg m2
Total Kinetic Energy of hoop,
KE = KErot + KEtran
KErot = 1/2 400 × (.1)2
= 2 J
KEtran = 1/2 100 × (.2)2
= 2 J
∴ Total Kinetic energy,
KE = 2 + 2 = 4 J
Work done to stop the moving hoop is equal to its KE which is 4 J
Rate this question :






















Find the ratio of the linear momenta of two particles of masses 1.0 kg and 4.0 kg if their kinetic energies are equal.
HC Verma - Concepts of Physics Part 1A man of mass 50 kg starts moving on the earth and acquires a speed of 1.8 m/s. With what speed does the earth recoil? Mass of earth = 6 × 1024 kg.
HC Verma - Concepts of Physics Part 1A ball of mass m is dropped onto a floor from a certain height. The collision is perfectly elastic and the ball rebounds to the same height and again falls. Find the average force exerted by the ball on the floor during a long time interval.
HC Verma - Concepts of Physics Part 1A ball of mass 0.50 kg moving at a speed of 5.0 m/s collides with another ball of mass 1.0 kg. After the collision the balls stick together and remain motionless. What was the velocity of the 1.0 kg block before the collision?
HC Verma - Concepts of Physics Part 1A block at rest explodes into three equal parts. Two parts start moving along X and Y axes respectively with equal speeds of 10 m/s. Find the initial velocity of the third part.
HC Verma - Concepts of Physics Part 1A railroad car of mass M is at rest on frictionless rails when a man of mass in starts moving on the car towards the engine. If the car recoils with a speed v backward on the rails, with what velocity is the man approaching the engine?
HC Verma - Concepts of Physics Part 1A ball of mass 50 g moving at a speed of 2.0 m/s strikes a plane surface at an angle of incidence 45o. The ball is reflected by the plane at equal angle of reflection with the same speed. Calculate (a) the magnitude of the change in momentum of the ball (b) the change in the magnitude of the momentum of the ball.
HC Verma - Concepts of Physics Part 1