Height of the hill = h = 500m
Speed of projection of packets = u = 125m/s
Distance of canon = 800m
Speed of canon = v = 2m/s
For time to be minimum, the packet should just pass the top of the hill and so the vertical component of velocity must be minimum.
Now let’s calculate the horizontal component of velocity.
Now, for time to reach the top of the hill,
Hence, 20 seconds is the time of flight.
Now, let’s find the horizontal distance between the canon and top of the hill.
R = uxt = 75m/s×10s =750m
Distance travelled by canon = 800m – 750m = 50m
Time taken by the canon =
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