Answer :

Given:
Height of the building = 11.8 m
Distance of the young man from the building = 7 m



The kid should be caught over 1.8 m from ground.
As the kid is slipping, his initial velocity u is 0.
Acceleration, a = 9.8 m/s2
Let s be the distance before which the kid has to be caught:


S= 11.8 − 1.8 = 10 m
Using the equation of motion, we get:





So, t =1.42 sec


This is the time in which the man should reach the bottom of the building to catch the kid.


Velocity with which the man should run:



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