A healthy young m

Given:
Height of the building = 11.8 m
Distance of the young man from the building = 7 m

The kid should be caught over 1.8 m from ground.
As the kid is slipping, his initial velocity u is 0.
Acceleration, a = 9.8 m/s²
Let s be the distance before which the kid has to be caught:

S= 11.8 − 1.8 = 10 m
Using the equation of motion, we get:

So, t =1.42 sec

This is the time in which the man should reach the bottom of the building to catch the kid.

Velocity with which the man should run: