Answer :

Speed of the shells = vo

Horizontal component of velocity of shells = vx = v0cosθ

Vertical component of velocity of shells = vy = v0sinθ

Maximum range = R =

We know, maximum range is achieved at θ = 45°

Time of flight = t =

Using kinematic equation,

-h = v0sinθt – gt2

Substituting the value of t,

-h = v0sinθ

Here, θ = 45° , hence sinθ = cosθ =

h = +

h = ∆x

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