Answer :

Speed of the shells = vo


Horizontal component of velocity of shells = vx = v0cosθ


Vertical component of velocity of shells = vy = v0sinθ


Maximum range = R =


We know, maximum range is achieved at θ = 45°


Time of flight = t =


Using kinematic equation,


-h = v0sinθt – gt2


Substituting the value of t,


-h = v0sinθ


Here, θ = 45° , hence sinθ = cosθ =


h = +





h = ∆x


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