A given coin has

Mass of a copper coin = 3 g

Atomic mass of copper atom, m = 62.92960u

The total number of atoms in the coin = N = Where,

NA = Avogadro’s number = 6.023 × 1023 atoms /g

Hence, N = = 2.868 × 1022

The number of neutron and Proton both in a 63Cu29 atom is respectively 34 and 29.

The mass defect Δm = mp + mn-mFe

And Binding energy is given by EB = Δmc2

Mass of a proton = 1.007825 u

Mass of a neutron = 1.008665 u

Mass defect = Δm = 29 × 1.007825 + 34 × 1.008665-62.92960 u = 0.591935u

Mass defect of the coin = Δm = 0.591935 × 2.868 × 1022 u = 1.69766958 × 1022 × 931.5 MeV/c2

Binding Energy = 1.581 × 1025MeV = 1.581 × 1025 × 1.6 × 10-13 J = 2.5296 × 1012 J

Hence, 2.5296 × 1012 Joules of energy is required to separate the nucleons of the coin.

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