A given coin has

Mass of a copper coin = 3 g

Atomic mass of copper atom, m = 62.92960u

The total number of atoms in the coin = N =

Where,

N_A = Avogadro’s number = 6.023 × 10²³ atoms /g

Hence, N = = 2.868 × 10²²

The number of neutron and Proton both in a ⁶³Cu₂₉ atom is respectively 34 and 29.

The mass defect Δm = m_p + m_n-m_Fe

And Binding energy is given by E_B = Δmc²

Mass of a proton = 1.007825 u

Mass of a neutron = 1.008665 u

Mass defect = Δm = 29 × 1.007825 + 34 × 1.008665-62.92960 u = 0.591935u

Mass defect of the coin = Δm = 0.591935 × 2.868 × 10²² u = 1.69766958 × 10²² × 931.5 MeV/c²

Binding Energy = 1.581 × 10²⁵MeV = 1.581 × 10²⁵ × 1.6 × 10^-13 J = 2.5296 × 10¹² J

Hence, 2.5296 × 10¹² Joules of energy is required to separate the nucleons of the coin.