Q. 53.8( 17 Votes )

A given coin has

Answer :

Mass of a copper coin = 3 g


Atomic mass of copper atom, m = 62.92960u


The total number of atoms in the coin = N =


Where,


NA = Avogadro’s number = 6.023 × 1023 atoms /g


Hence, N = = 2.868 × 1022


The number of neutron and Proton both in a 63Cu29 atom is respectively 34 and 29.


The mass defect Δm = mp + mn-mFe


And Binding energy is given by EB = Δmc2


Mass of a proton = 1.007825 u


Mass of a neutron = 1.008665 u


Mass defect = Δm = 29 × 1.007825 + 34 × 1.008665-62.92960 u = 0.591935u


Mass defect of the coin = Δm = 0.591935 × 2.868 × 1022 u = 1.69766958 × 1022 × 931.5 MeV/c2


Binding Energy = 1.581 × 1025MeV = 1.581 × 1025 × 1.6 × 10-13 J = 2.5296 × 1012 J


Hence, 2.5296 × 1012 Joules of energy is required to separate the nucleons of the coin.


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