Q. 143.9( 14 Votes )

A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4.

Plot a velocity–time graph for the same.

Answer :

From the graph, we have:

Initial velocity (u) = 0

Now, Velocity(v) = displacement/time

Therefore, the velocity after 50s =?

v = 100/50 = 2ms-1

Ans, the velocity after 100s,

Here, the displacement = 0

Then, time = 100s


V = 0/100 = 0

Velocity – time graph plotted from the above data is:

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