Q. 115.0( 1 Vote )
‘J’ is mechanical equivalent of heat a conversion factor between two different units of energy: calorie to joule
From the graph we can write
We know that work done by the gas is given as
Work done in path AB=0 as VA=VB.
Work done in path CA ΔW1=PA(VA-VC)
Work done in path BC ΔW2= Pavg(VC-VB)
Total work done in process ABCA=ΔW=ΔW1+ΔW2
We know that in the cyclic process the system returns to its initial state. So, change internal energy in the cyclic process will be zero as internal energy is a state function.
From first law of thermodynamics, we know that,
Where ΔQ=heat supplied to the system
ΔU=change in internal energy
ΔW=work done by the system
Since ΔU=0, first law becomes
But it is given in question that ΔQ=2.4cal
∴ value of ‘J’ is 4.17J/cal.
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