Answer :

Given, P1 = 100 KPa = 105 Pa, V1 = 400 cm3 , T1 = 300 K,


CP/CV = 1.5


(a)Suddenly compressed to V2 = 100 cm3 I.e. it is an adiabatic process


PVγ = const.


I.e.



Also,





(b) Even though the container is slowly compressed the walls are adiabatic so heat transferred is 0.


Thus the values remain same


i.e. P2 = 800 KPa, T2 = 600 K.


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