Q. 7

# A gas cylinder ha

We know ideal gas equation

PV=nRT

Where V= volume of gas

R=gas constant

T=temperature

n=number of moles of gas

P=pressure of gas.

Given

Maximum pressure Pmax=P2=1.0 × 106 Pa

Pressure of gas P1=8.0 × 105 Pa

Temperature of gas T1=300K

Since the volume has not been changed therefore,

V1=V2=V

Hence number of moles will also be same n1=n2=n

Temperature at which the cylinder will break=T2

Since n1 =n2 =n

Therefore,

T2 =375K

The temperature at which the cylinder will break=375K.

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