Answer :

Given:



Resistance of galvanometer coil, G = 15 Ω


Current for full scale deflection, Ig = 4mA


Upper limit of ammeter I = 6A


A galvanometer can detect only small currents and their direction. Thus, to measure large currents it is converted into an ammeter. A galvanometer can be converted into an ammeter by connecting a low resistance called shunt resistance in parallel to the galvanometer


Let shunt resistance = S


We know that value of shunt is given by:


…(1)


By plugging the values of Ig, I and G into Equation (1), we get,



S = 10mΩ


For converting the galvanometer into an ammeter of range 0-6 we can add a shunt of resistance 10mΩ.


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