Q. 133.7( 3 Votes )

a. Followin

Answer :

a. E0(Zn2+/Zn) =−076V


E0(Ag+/Ag) =080V


1F=96,500Cmol−1J


n= 2


E0cell = E0(Ag+ / Ag) – E0(Zn2+ / Zn)
= 0.80- (- 0.76)
= 1.56V
ΔG0 =−nFE0
=-2 × 96500 × 1.56
= -301080 joules / mol
= -301.080 K/ mol


b. 0m for strong electrolyte is obtained as intercept from plot of m verses c whereas 0m for weak electrolyte is obtained from Kohlrausch's law :


Λ0m=λ0++λ0-


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