Q. 194.2( 32 Votes )

A first order rea

Answer :


Time t = 40 min

When 30% decomposition is undergone, 70% is the concentration.

We know, time taken

Where, k- rate constant

[R]° -Initial concentration

[R]-Concentration at time ‘t’

258.23 = (2.303/k)

We know, Half-life t1/2 = 0.693/k

Which can be written as, t1/2 = 0.3010 × (2.303/k)

t1/2 = 0.3010 × 258.23

t1/2 = 77.72 min

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Note: In the follChemistry - Exemplar

Which of the follChemistry - Exemplar