Q. 224.0( 1 Vote )

A first order <sp

Answer :

[R]0 = 100, [R] = 100- 25, t= 10 minutes


By the formula,


k = log


k = log


k = log


k = log4 – log 3


k = (0.6021 – 0.4771)


Therefore, k = 2.88 10-2 min-1


For a first order reaction,


t1/2 =


t1/2 =


t1/2 = 24.06 minutes


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