Q. 114.7( 3 Votes )

A. Find the value

Answer :

Given,


Inductance, L = 100 mH = 100×10-3 H,


Capacitance, C = 2μ F = 2× 10-6 F


Resistance, R = 400 Ω


ω = 1000


(A) For phase difference,



Where, ω = angular speed of cycles


L = inductance


C = Capacitance


R = resistance


Thus,






= 1350


And current is in leading phase since


(B) Unit power factor,



Where,


R = resistance


L = Inductance


C’ = total capacitance


Given, unit power factor, cosϕ = 1






= 10 μF


Thus, additional capacitance needed in parallel,


Ca = C’ – C


= 10 μF – 2 μF


= 8 μF


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