Answer :

Concepts/Formula used:

Ohm’s Law:

Potential Difference (V) across a resistor of resistance R when current I passes through it is given by Ohm’s law:

Kirchhoff’s junction rule:

The sum of currents entering a junction is equal to the sum of currents leaving it.

Kirchhoff’s loop rule:

The sum of potential differences around a closed loop is zero.

Energy stored by a capacitor:

If the potential difference between the two conductors of the capacitor is V and its capacitance is C, its energy is given by:


Using Kirchhoff’s law on loop FEABF,


Using Kirchhoff’s law on loop ACDBA,


Solving (1) and (2), we get



At steady state, no current passes through the capacitor; hence, the results are the same as in (a).

Now, the potential as the capacitor is in parallel with the 20Ω resistor,

Hence, the energy stored by the capacitor is 32μJ.

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