Q. 15

A farsighted person cannot see objects placed closer to 50 cm. Find the power of the lens needed to see the objects at 20 cm.

Answer :

Given that


Far point where object is placed ,u= -20cm


Distance between eye-lens and retina = v = -50 cm


Then using lens formula, the maximum focal length can be calculated as-



Substituting the values,




Now the Power of the lens becomes-



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