# A driver of a car travelling at 52 km h-1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 3 km h-1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied?

Given:

Firstly, for the first car:

Initial speed, u = 52 km/h2

(We know that 1 km=1000 m and 1 hour=3600 seconds)

=

= 14.4 m s-1 (i)

Final speed, v = 0 (As the car stops) (ii)

Time taken, t = 5 s (iii)

Now, for the second car:

Initial speed, u = 3 km/h

(We know that 1 km=1000 m and 1 hour=3600 seconds)

= 0.833 m/s (iv)

Final speed, v = 0 (As the car stops) (v)

Time taken, t = 10 s (vi)

In the graph, we will plot time taken in X-axis and speed in the Y-axis. In the graph the sloping point AB is the speed-time graph for the first car and the sloping point CD is the speed-time graph for the second car.

Now we have to find the distance traveled under the graph line AB = Area under triangle AOB

= × base × height

= × 5 × 14.4

= 36 m (vii)

Now we will find the distance travelled under the line CD = Area under triangle COD

= × base × height

= × 0.833 × 10

= 4.1 m (viii)

Therefore, from (vii) and (viii) it is clear that the second car travels farther as compared to the first after the application of brakes.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Learn The Use of Equations of Motion37 mins
Second Equation of Motion48 mins
Understanding Motion60 mins
Interactive Quiz - Motion29 mins
Velocity Time Graph46 mins
Champ Quiz | Motion under gravity46 mins