Q. 18

(a) Draw the stru

Answer :

(a) Geometrical isomers of [Fe(NH3)2 (CN)4]- are:



Cis Trans


(b) Oxidation state of Ni in [NiCl4]2- is +2.


Electronic configuration of Ni2+: 3d8 4s0


Since, Cl is a weak ligand it will not be able to pair the unpaired electrons. So, 2 unpaired electrons are left in 3d orbital because of which it is paramagnetic. The hybridisation scheme is as shown in diagram given below-



Oxidation state of Ni in [Ni(CO)4]is 0.


Electronic configuration of Ni: 3d8 4s2


Since, CO is a strong ligand, the 4s electrons paired up in 3d orbital and sp3 hybridisation is formed. As there will be no unpaired electron the complex is diamagnetic.


OR


(a) Ambidentate ligands are the ligands which can bind the central atom through 2 different donor atoms. E.g. CN- and NC-, it can bind through N or C atom. Other example is NO2- or ONO-.


(b) Spectro chemical series is an experimental series in which ligands are arranged in increasing order of their field strength.


I - < Br- < SCN- < Cl- < S2- < F- < OH- < C2O42- < H2O < NCS- < edta4- < NH3 < en < CN- < CO


(c) Heteroleptic complexes are those in which metal i.e. the central atom is bound to more than one kind of donor groups. E.g. [Co(NH3)4Cl2]+.


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