Answer :

We know that,

Force between the plates of the capacitor is given by



Where,


Q=charge on the capacitor


A=area of plates


Derivation:


Suppose charge Q and -Q are provided on plates of capacitor of area A.


Since, F=QE


Where


Q is the test charge on the point charge


E is the electric field intensity.


Field due to charge Q on one plate is



Force on the plate with charge -Q will be



Considering magnitude, each plate applies a force of


Each.


On increasing a dielectric slab between the plates of the capacitor, the charge on the plates remains constant as the plates are isolated) .


Since, area of plates does not change, force between the plates remain constant.

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