Answer :

When a dielectric slab of dielectric constant K is introduced between the plates of the capacitor, the net electric field in the dielectric becomes


Where,


E0 is the electric field when there is vacuum between the plates.


K is the dielectric constant of the dielectric


The net electric field is due to charges +Q, -Q and due to induced charges +Q’,-Q’in opposite direction).


So, the net electric field becomes




Where,


Q’=induced charge due to dielectric


Q=charge on the capacitor in vacuum


K=dielectric constant


Since dielectric constant K>1


Q’<Q


Therefore, on inserting a dielectric slab between plates of capacitor the induced charge Q’ is less than Q.

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