Q. 84.8( 4 Votes )
A current of 2A enters at the corner d of a square frame abcd of side 20 cm and leaves at the opposite corner b. A magnetic field B = 0.1 T exists in the space in a direction perpendicular to the plane of the frame as shown in figure. Find the magnitude and direction of the magnetic force on the four sides of the frame.
Answer :
Given-
square of side, l = 20 cm
Electric current passing through the wire, I = 2 A
Magnetic field, B = 0.1 T
The direction of magnetic field is perpendicular to the plane of the frame, coming out of the plane.
Given in the question, that current enters at the corner d of the square frame and leaves at the opposite corner b.
Hence, angle between the frame and magnetic field, θ = 90°
Now, we know-
Magnetic Force on a Current carrying wire is given by
where,
B= magnetic field
I = current
L = length of the wire
and θ = the angle between B and l
Hence, magnetic force,
For wire along the sides da and cb,
The direction of force can be found using Fleming’s left-hand
rule.
which states that –
whenever a current carrying conductor is placed inside a magnetic field, a force acts on the conductor, in a direction perpendicular to both the directions of the current and the magnetic field
Thus, the direction of magnetic force will be towards the left.
now, for wires along sides, dc and ab,
Again, here the direction of force can be found using Fleming’s left-hand rule.
Thus, the direction of magnetic force will be downwards.
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