Answer :

Let the no. of atoms of A forming the hcp be x

So, the no. of octahedral voids = x

And the no. of tetrahedral voids = 2x

As the atoms of element A forms HCP and atoms of B occupies 2/3 of the octahedral voids, so the ratio of atoms of A and B are x:(2/3)x

• A:B=3:2

• The formula of the solid is A3B2

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