Answer :

Let the no. of atoms of A forming the hcp be x


So, the no. of octahedral voids = x


And the no. of tetrahedral voids = 2x


As the atoms of element A forms HCP and atoms of B occupies 2/3 of the octahedral voids, so the ratio of atoms of A and B are x:(2/3)x


• A:B=3:2


• The formula of the solid is A3B2


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