Answer :

Let's assume that the edge of the ice cube just before it leaves contact with glass be “x cm” and its height of water at that time be “h cm”.


Given, inner diameter is 6 cm. Therefore, radius would be 3 cm.


Initial edge of the ice cube is 4 cm.


Let the density of water be and that of ice is


Now, the weight of the remaining ice will be balanced by the buoyant force provided from the melted water.



The mass of the ice is




Volume of water formed is



Substituting the value of h, we get


(ANS)


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