Q. 164.0( 57 Votes )

A cricketer can t

Answer :

Given:


Maximum horizontal distance travelled by the ball=Range =R= 100m


Explanation: We know that range is maximum if the angle of projection is 45˚.



Figure showing projectile motion


(ϕ = 45˚)



u = 31.304 m/s


Height to which the ball is thrown = H


Since the final velocity of the ball is zero i.e. v= 0


From the relation v2-u2=2as


0 - 31.3042 = 2×9.8×H (s=H)


H= 50m


The cricketer can throw the ball to a height of 50m above the ground.


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