Q. 164.0( 57 Votes )

A cricketer can t

Answer :


Maximum horizontal distance travelled by the ball=Range =R= 100m

Explanation: We know that range is maximum if the angle of projection is 45˚.

Figure showing projectile motion

(ϕ = 45˚)

u = 31.304 m/s

Height to which the ball is thrown = H

Since the final velocity of the ball is zero i.e. v= 0

From the relation v2-u2=2as

0 - 31.3042 = 2×9.8×H (s=H)

H= 50m

The cricketer can throw the ball to a height of 50m above the ground.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A particle is proPhysics - Exemplar

A particle fallinPhysics - Exemplar