A constant force

Given the initial velocity u =0, implies initial K.E =0 Acceleration a= force/mass = 2.5/0.015 = 500/3 m/ Displacement = 2.5m, now let us evaluate final velocity using equations of uniform motion , substituting the given values and solving for v we get v= 2500/3m/sec Therefore the final kinetic energy = , now from the work energy theorem we have W =

Now let us evaluate the times taken for the displacement using the equation of uniform linear motion v= u+a× t

Thus, we get t = 0.17sec, by substituting for v,u and a

Now as per the definition of power P =Work/time =