# A conductin

Given:

Radius of charged sphere, r = 10 cm

Electric field, 20 cm away from centre of sphere, E = 1.5 × 103 NC-1

We know that, electric field intensity at a point P, located at a distance R, due to net charge q is given by,

…(1)

Now plugging the values of q and R in equation (1)

q = 4 × π × ε0 × R2 × E

q = 4 × 3.14 × 8.85 × 10-12N-1m-2C-2 × (0.2m)2 × 1.5 × 103C

q = 6.67 × 10-9C

The net charge on the sphere is -6.67 × 10-9C. Since the electric field points radially inwards, we can infer that charges on sphere are negative.

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